An electron moves with a velocity 1 × 10 3 m/s in a magnetic field of induction 0.3 T at an angle 30°. If 
of electron is 1.76 × 10 11 C/kg, the radius of the path is nearly:
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If electron moves in a magnetic field at an angle θ (other than 0°, 180° or 90°), its velocity can be resolved in two components one along 
and another perpendicular to 
. Let thetwo components be V|| and v ⊥ . Then
The component perpendicular to field (v ⊥ ) gives a circular path and the component parallel to field (V||) gives a straight line path. The resultant path is, helix as shown in figure.
The radius of this helical path is
r = 
= 
or r = 
Given, v = 1 × 10 3 m/s, B = 0.3T, θ = 30°
= 1.76 × 10 11 C/kg
r = 
= 
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